Question

Q34. The equation of straight line passing
through the point (1, 2) and parallel to the
line y = 3x + 1 is
(A) y + 2 = x + 1
(B) y + 2 = 3 (x + 1)
(C) y - 2 = 3 (x - 1)
(D) y - 2 = x - 1​

Answer 1

Answer:

   So, we must find the equation parallel to the given line y = -3x + 1 that passes through the point (-1,2). So, we will need that point and use the same slope from the given line since parallel lines have the same slope by definition! Then, we plug those values into the point-slope formula such that,

y - y1 = m(x - x1)

y - 2 = (-3)(x - (-1))

y - 2 = (-3)(x + 1)..........Then distribute the -3 inside such that

y - 2 = -3x - 3..........Finally, add 2 to both sides to get

y = -3x - 1

I hope this helped!

Step-by-step explanation: