Q35. A car accelerates uniformly rom 18 km h- to 36 km h-in 5 s. Calculate
(a) the acceleration and
(b) the distance covered by the car in that time.
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Answer:
Acceleration =Change in Velocity /Time
Change in Velocity =36-18km/h=5m/s
Time =5second
Acceleration =5/5=1m/s2
Equation of motion, s=ut+(1/2)at2
u=18km/h=5m/s
t=5s
a=1m/s2
s=(5*5)+(1/2*1*5*5)
s=25+12.5 i. e., s=37.5m
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