Question

Q38. A wire carries a current of 1 Amp. How many electrons passes any point of the wire each second : O (A) 63 x 108 electrons / sec O (B) 6.3 x 1018 electrons / sec O (C) 63 electrons / sec O (D) 630 electrons / sec N Mark X Clear Next Previous Hide Question Panel​

Answer 1

1 ampere current is present in a wire. So, it means 1 Coulomb of charge are passing in 1 second.

$1 \: amp = \dfrac{1 \:C }{1 \: sec}$

So, the number of electrons passing every second is :

$no. \: of \: electrons = \dfrac{charge}{e}$

$\implies no. \: of \: electrons = \dfrac{1}{1.6 \times {10}^{ - 19} }$

$\implies no. \: of \: electrons = 6.25 \times {10}^{18}$

$\implies no. \: of \: electrons \approx 6.3\times {10}^{18}$

So, number of electrons passing every second is 6.3 × 10¹⁸.