Question

Q4. A car acquires a velocity of 36km/h in 10 seconds
starting from rest. Find
(i) Acceleration
(ii) Distance travelled in this time.

Answer 1

Answer:

☛ Acceleration, a = 1 m/s²

☛ Distance travelled in this time, s = 50 m

Explanation:

Given:

☛ Final velocity, v = 36 km/h or 10m/s

☛ Initial velocity, u = 0 m/s

∵ The car starts from rest.

☛ Time taken to acquire the velocity, t = 10 s

To Find:

☛ Acceleration, a = ?

☛ Distance travelled in this time, s = ?

Solution:

We know,

v = u + at

Substituting values,

⇒ 10 = 0 + a×10

⇒ 10a = 10

⇒ a = 1 m/s² ...(1)

Similarly,

2as = v² - u²

Substituting values,

⇒ 2×1×s = 10² - 0² { from (1) }

⇒ 2s = 100

⇒ s = 50 m ...(2)

From (1) and (2),

Acceleration, a = 1 m/s²

Distance travelled, s = 50 m

Answer 2

Answer:

first we will convert 36km/hr in m/s , so we will get 10m/s.

Now,

acceleration=(v-u)/t

=10-0/t [u=0 because the car was at rest]

=10/10=1m/s^2

distance =ut+1/2×at^2

=0×10+1/2×1×(10)^2

=0+1/2×1×100

=50

Therefore , acceleration=1m/s^2 and distance=50m.

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