Question

Q4 A girl walks 50m towards East and then 120m towards North. The distance of the girl from the starting point is:
(a) 300m
(b) 150m
(c) 130m
(d) 100m​

Answer 1

ANSWER

c) 130m

EXPLAINATION

we can use Pythagoras theorem

so AB=x

BC=50

CA=120

Pythagoras theorem

AB^2=BC^2+CA^2

AB^2=(50)^2+(120)^²

AB^2=2500+14400

AB=√16900

AB=130

So,the answer is 130m