Question

Q4 A man grows into a giant such that his linear dimensions increase by a factor of 9. Assuming that his
density remains same, the stress in the leg will change by a factor of
b) 1/9 c) 81 d) 1/81
a) 9
how is can be done
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Answer 1

Explanation:

1. the answer is a as the density remains same in the stress the label changed by a factor of it is the answer because the b equals 281 + 89

ext answer will be the be as it is by divided by 9 as a factor of 9 is divided by 4 a.m. and grows it has done as 9

Answer 2

Answer:

9

Vf /Vi= 9^3

density remains same

mass=volume

Mf/Mi=9^3

(area)f/(area)i=9^2

stress =mass*g/area

=(mf/mi)(Af/Ai)

=9^3/9^2

=9