Physics, asked by aditimani2007, 1 month ago

Q4: A man throws a ball vertically upwards with a speed of 500m/s. if the mass of the ball is
150g find:
i. The initial momentum of the body.
ii. What would be the momentum at the highest point of flight?
PLEASE SHOW WITH WORKING

Answers

Answered by Anonymous
93

GIVEN :-

  • Initial velocity of ball = 500m/s
  • Mass of the ball = 150g
  • Acceleration due to gravity = -10m/s²

To Find :-

  • The initial momentum of the body.
  • What would be the momentum at the highest point of flight

Formulae and concept used :-

  • momentum of object = mv, mu
  • At highest point final velocity is 0.

Now,

→ Initial momentum of body = mu

→ 0.15 × 500 = 75kgm/s

→ Final momentum of body = mv

→ 0.15 × 0 = 0kgm/s

Hence,The Initial momentum of body iz 75kgm/s and final momentum is 0kgm/s

Answered by MяMαgıcıαη
161

Answer:

‣ Initial momentum of the body \mapsto\:{\boxed{\tt{\red{75\:kgm/s}}}}

‣ Momentum at the highest point of flight \mapsto\:{\boxed{\tt{\pink{0\:kgm/s}}}}

Explanation:

Given information,

A man throws a ball vertically upwards with a speed of 500 m/s. If the mass of the ball is 150 g. Find:

❶ The initial momentum of the ball.

❷ What would be the momentum at the ㅤhighest point of flight?

i.e,

  • Initial velocity of body (v) = 500 m/s
  • Mass of body (m) = 150 g
  • Initial momentum = ?
  • Final momentum = ?

Converting units of mass from 'g' to 'kg',

  • \boxed{\underline{\underline{\bf{\green{1\:kg = 1000\:g}}}}}\:\bf{\dag}

➻ Mass in kg = \sf {\cancel{\dfrac{150}{1000}}}

Mass in kg = 0.15 kg

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Now,

Finding initial momentum of the ball ::

  • \boxed{\underline{\underline{\bf{\blue{Initial\:momentum = mu}}}}}\:\bf{\dag}

Where,

  • m = mass of ball
  • u = initial velocity of ball

We have,

  • m = 0.15 kg
  • u = 500 m/s

Putting all values,

➻ Initial momentum = 0.15 kg × 500 m/s

➻ Initial momentum = 75 kgm/s

  • Henceforth, initial momentum of the ball is 75 kgm/s.

Finding momentum at highest point of flight ::

  • \boxed{\underline{\underline{\bf{\purple{Final\:momentum = mv}}}}}\:\bf{\dag}

Where,

  • m = mass of ball
  • v = final velocity of ball

We have,

  • m = 0.15 kg
  • v = 0 m/s

[v = 0 m/s, Because at highest point ball will experiences final velocity = 0 m/s]

Putting all values,

➻ Final momentum = 0.15 kg × 0 m/s

Final momentum = 0 kgm/s

  • Henceforth, final momentum i.e, momentum at the highest point of flight of the ball is 0 kgm/s.

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Anonymous: Well explained answer :)
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