Q4. A nail has 2.0m’at one end and 1/100m’ at the other end. A force of 1000 N is applied, calculate the pressure exerted on the wall.
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The area of first end of nail is 2 m2
Area of other end is 1/100 = 10-2 m2 = 0.01 m2
Force applied = 1000 gwt = 1000 × 10 = 10000 N ...(Since, g =10 m/s2)
Pressure is applied at first end. This means other end whose area is 0.01 m2 is in contact with the wall.
Thus, the pressure acting on a wall is
P = Force/ Area = 10000/0.01 = 1000000= 106 N/m2
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