Q4.A particle moves along the x-axis. The function x(t) gives the particle's position at any time t≥0: x(t)=t3−3t2+7t−6 What is the particle's velocity v(t) and acceleration a(t) at t=4?
Answers
Answered by
3
Answer:
is it OK
Explanation:
I hope it's helpful please
mark me
as brainliast.
Attachments:
Answered by
2
Answer:
For velocity:
dx/dt = v
3t^2 -6t + 7 =v , at t=4 ------------- v = 3(16) -6(4) + 7 = 31 m/s
For acceleration:
dv/dt =a
6t - 6 = a , at t=4 s ----------------- a = 6(4) - 6 = 18 m/s^2
Hope it helps, friend!
MARK ME AS BRAINLIEST!
Similar questions