Physics, asked by deepalisaxena1418, 7 months ago

Q4.A particle moves along the x-axis. The function x(t) gives the particle's position at any time t≥0: x(t)=t3−3t2+7t−6 What is the particle's velocity v(t) and acceleration a(t) at t=4?

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Answered by Abhinandhan
3

Answer:

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Explanation:

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Answered by Anonymous
2

Answer:

For velocity:

dx/dt = v

3t^2 -6t + 7 =v , at t=4 ------------- v = 3(16) -6(4) + 7 = 31 m/s

For acceleration:

dv/dt =a

6t - 6 = a , at t=4 s ----------------- a = 6(4) - 6 = 18 m/s^2

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