Question

Q4. A proton is confined to a cubic box, whose sideshave length 10-12m. What is the minimum kineticenergy of the proton? The mass of proton is1.67x10-27 kg and Planck's constant is6.63x10-34 Js.1. 1.1x10-17)2.3.3x10-17)3. 9.9x10-17)4. 6.6x10-17)give the complete solution​

Answer 1

Answer:

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Explanation:

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Answer 2

Given info : A proton is confined to a cubic box, whose sideshave length 10¯¹² m. The mass of proton is 1.67 × 10^-27 kg and Plank's constant is 6.63 × 10¯³⁴ Js.

To find : the minimum kinetic energy of proton is ..

solution : Minimum kinetic energy of proton is given by, K = 3h²/8ma²

here, h = 6.63 × 10¯³⁴ Js , m = 1.67 × 10^-27 kg , a = 10¯¹² m

so, K = {3 × (6.63 × 10¯³⁴)²}/{8 × 1.67 × 10^-27 × (10¯¹²)²}

= (3 × 43.9569 × 10^-68)/(8 × 1.67 × 10¯⁵¹)

= 9.9 × 10^-17 J

Therefore the minimum kinetic energy of proton is 9.9 × 10^-17 J.