Question

Q4 A rectangular piece of land
measures 18 m by 12.5m. It is to be
fenced with five rows of wire all
along its four sides, find the cost of
fencing if one m of wire costs * 24.​

Answer 1

Answer:

a rectangular price of land measures 18 m by 12.5 m .it is to be fenced with five rows of wire all along its four sides find the cost of fending if one m of wire cost 24 ?

Step-by-step explanation:

multiple × 24 into 18 m = 432 is your answer

Answer 2

Answer :-

• Total Cost of Fencing = 7320 Rs

Given :-

• Length of Field = 18 m
• Breadth of Field = 12.5 m
• Total Rounds of fencing = 5

To Find :-

• Total Cost of Fencing = ?

Explanation :-

As above given, we have fence the field it means we need to find the perimeter of the field.

Finding the Perimeter of Field with 5 Rounds,

$\blue { \boxed { \bf \odot \: Perimeter \: of \: Field = 2 \: (L+B) \: \odot }}$

$\rm : \: \implies 2 \: (L + B) \times 5 = Perimeter \: of \: Field \: with \: \underline{\bold{5 \: Rounds}}$

$\rm : \: \implies 2 \: (18 + 12.5) \times 5 \: m$

$\rm : \: \implies (2 \times 30.5 \times 5) \: m$

$\rm : \: \implies (10 \times 30.5) \: m$

$\green { \bf : \: \implies 305 \: m \; \; \; \star}$

Finding the Total Cost if Painting,

$\rm : \: \implies Cost \: of \: Fencing \: 1 \: m \: of \: wire = \bold{24 \: R_S}$

$\rm : \: \implies Cost \: of \: Fencing \: 305 \: m \: of \: wire,$

                 $\rm = (305 \times 24) \: R_S$

                $\red { \underline { \boxed { \bf = 7320 \: R_S }}}$

Hence, the cost of fencing (5 Rounds) the Rectangular field is 7320 Rs