Question

Q4: A sled with a mass of 9.00 kg moves in a straight line on a
frictionless horizontal surface. At one point in its path its speed is
4.00 m/s; after it has traveled 3.00m beyond this point, it speed is
6.00 m/s. use the work-energy theorem to find the force acting on
the sled, assuming that this force is constant and that it acts in the
direction of the sled's motion.​

Answer 1

Answer:

F = 30N

Explanation:

KE gain = WD by force

(1/2) m (v² - u²) = Fs

(1/2) (9) (6²-4²) = 3F

F = 30N