Question

Q4. A stone is released from the top of a tower of height 19.6 m. Then its final velocity just before touching
the ground will be:
(a) 384.16 m/s
(b) 196 m/s
(c) 19.6 m/s
(d) 3841.4 m/s
(Take g = 9.8 m/s2)​

Answer 1

Answer:

2as=v2-u2

u=0; s=19.6; g=a=9.8

2×9.8×19.6=v2-0^2

384.16=v2

v=√384.16

v=19.6 m/s

hope it helps