Math, asked by Anshsaroha, 7 months ago

Q4. A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 13 cm, 14 cm and 15 cm and the parallelogram stands on the base 14 cm, find the height of the parallelogram.

Answers

Answered by itzshrutiBasrani
2

Step-by-step explanation:

Given,

Sides of tri.- 13,14 and 15 cm

base of //^gm = 14 cm

☘ By Heron's Formula.-

s= (13+14+15) cm/2=42/2= 21 cm.

>> √ s(s-a)(s-b)(s-c)

>> √ 21(21-13)(21-14)(21-15)

>> √ 21× 8 × 7 × 6

>> √ 3×7× 4×2 × 3×2×7

>> 168 cm^2

☘ Now,h of //^gm.-

>168=14×h

> 168/14=h

> h= 12 CM

Answered by madhumithakannan2005
0

Answer:

h=12

Step-by-step explanation:

same base

so area of triangle=area of parallelogram

by using heron's formula

area of triangle= 84 cm2

therefore

area of parallelogram= 1/2*b*h

84=1/2*14*h

h=12

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