Q4 ALL SUM
PLZZZ SOLUTION PHOTO SEND me
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sahil23446:
plzz solution photo send me
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Answered by
5
hlw mate....
1) (10)^6/5 - 1/ 5 = (10) ^(6-1)/5 = (10)^5/5 = (10)^1 =10
2) (5)^8/3 -2 /3 = (5) ^ (8-2)/3 = (5)^6 /3 = (5)^2 =25
3) [9^5/4]-4/5 = [9]^(5/4)*(-4/5) =[9] ^(-20/20) = [9]^(-1)= 1/9
4) [16^ (3/2)]^1 /3 = [ 4^2*3/2 ]^1/3 = [4]^3*1/3 =[4]^1 =4
5) [(343)^7 /5 ] ^10/7 = [ (3)^5*7/5]^10/7 = [(3)^7]^10/7 = [3]^7*10/7 = [3]^10 = 59049
hope it helps u
1) (10)^6/5 - 1/ 5 = (10) ^(6-1)/5 = (10)^5/5 = (10)^1 =10
2) (5)^8/3 -2 /3 = (5) ^ (8-2)/3 = (5)^6 /3 = (5)^2 =25
3) [9^5/4]-4/5 = [9]^(5/4)*(-4/5) =[9] ^(-20/20) = [9]^(-1)= 1/9
4) [16^ (3/2)]^1 /3 = [ 4^2*3/2 ]^1/3 = [4]^3*1/3 =[4]^1 =4
5) [(343)^7 /5 ] ^10/7 = [ (3)^5*7/5]^10/7 = [(3)^7]^10/7 = [3]^7*10/7 = [3]^10 = 59049
hope it helps u
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Answered by
7
+ - ki mistake hoe sakti hai
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