Question

Q4. An object is kept at 20 cm from a
lens. Image of the object is found on the
opposite side of the lens at 40cm from
the lens. Find the magnification
produced by the lens. ​

Answer 1

$\boxed{\bf{\green{\longrightarrow Given}}}$

• u = -20 CM
• v=(+40cm)

$\boxed{\bf{\</strong><strong>r</strong><strong>e</strong><strong>d</strong><strong>{\longrightarrow </strong><strong>Solution</strong><strong>:</strong><strong>}}}$

• Since Image is formed on other side of lens it has to be a convex lens
• Using magnification formulae for lens:-
• $m = \frac{v}{u} = \frac{40}{ - 20}$
• $m = - 2cm$
• Therefore the image is real and inverted, and is enlarged
• Also object is placed between F and 2F of the lens to get Image beyond 2F on other side..

Hope it helps!