Question

Q4. An object is placed at a distance of 20cm from a convex mirror of focal length 25cm. Calculate the position of the image. Discuss its nature

Answer 1

$\boxed{ \bf \: Hello \: there !!}$


• Given that -

Object distance , u = -20 cm

focal length , f = + 25 cm


• using mirror formula

$\boxed{\frac{1}{f} = \frac{1}{v} + \frac{1}{u} }\\ \\ \rightarrow \: \frac{1}{v} = \frac{1}{25} + \frac{1}{20} \\ \\ \rightarrow \boxed{ \bf v =11.12 \: cm } \\ \ \\ \\ \underline{\ nature \: and \: position\: of \: the \: image \: } \\ \\ \rightarrow \: diminished \: \\ \\ \rightarrow \: beyond \: the \: miror \: \:$

Answer 2

HEY!!

_____________________________

▶f = 25

▶u = -10

▶1/f = 1/v + 1/u

▶1/25 = 1/v - 1/10

▶1/25 + 1/10 = 1/v

▶2/50 + 5/50 = 1/v

▶7/50 = 1/v

▶v = 50/7

▶v = 7.143 (approx...)

✔✔The image formed will be virtual and erect.