Math, asked by anurag1699, 2 months ago

Q4: Barry's age is twice that of Clyde. Five years
ago Barry was three times older than Clyde. Find
the age of both.​

Answers

Answered by Anonymous
522

Given :-

Barry's present age is twice that of Clyde.

Five years ago, Barry was three times older than Clyde.

To Find :-

Age of both.

Solution :-

Let the present ages of Barry and Clyde be x and y respectively.

According to the question, There are two conditions of different time :-

Case 1 (Present)

Barry's present age is twice that of Clyde.

This can be expressed as,

⇒ x = 2y

⇒ x - 2y = 0 ...(i)

Let's find the other linear equation in two variables with the help of the second case,

Case 2 (Past , 5 years ago)

Because this condition holds true 5 years ago hence 5 must be subtracted from both ages.

⇒ (Barry's age - 5) = 3(Clyde's age - 5)

⇒ x - 5 = 3(y - 5)

⇒ x - 5 = 3y - 15

⇒ x - 3y = -10 ...(ii)

Subtracting (ii) from (i), [ As the coefficient of x is same in both the equations, Hence subtracting the equations would eliminate x from the resultant equation and then we can find the value of y ]

⇒ x - 2y - (x - 3y) = 0 -(-10)

⇒ x - 2y - x + 3y = 10

⇒ 3y - 2y = 10

⇒ y = 10

Substitute value of y in eq.(i), we get x

⇒ x - 2y = 0

⇒ x = 2(10)

⇒ x = 20

Hence, Present age of Barry is 20 years while that of Clyde is 10 years.

Answered by llMrsVampirell
2

Answer:

ago Barry was three times older than Clyde. Find

the age of both.

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