Q4. Calculate the force of gravitation between a man weighing 60 kg and a boy weighing 20
kg standing 2 metres apart.
Answers
Answer:
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Explanation:
Mass of the man (m₁) = 80 kg
Mass of the boy (m₂) = 60 kg
Distance between the man and the boy
(d) = 2m
Gravitational constant (G) = 6.7 × 10-¹¹ N m²/kg²
The force exerted by the man on the boy is given by the formula for Newton's Universal law of gravitation, i.e.
\boxed{F \: = G \frac{m1m2}{d2} }
Putting the given value in the above formula, we get
F \: = \frac{6.7 \times {10}^{ - 11} N {m}^{2}/ \: {kg}^{2} \times 80kg \: \times 60kg }{ {(2m)}^{2} }
= \frac{6.7 \times {10}^{ - 11} \times 80 \times 60(N {m}^{2} {kg}^{2} ). {kg}^{2} }{4 {m}^{2} }
F \: = 8.04 \times {10}^{ - 8} n
Thus, the gravitation force exerted by the man on the boy is 8.04 × 10-⁸ N.
This is an extremely small force.
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