Q4) Calculate torque acting on a disc rotating about transverse axis having mass of 2 kg, radius 0.5m acted upon by angular acceleration of 2 rad/s²
1 point
a) 50 × 10⁻²Nm
b) 25 × 10⁻²Nm
c) 2.5 × 10⁻²Nm
d) 5.0 × 10⁻²Nm
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Answer:
Moment of inertia I=
2
mr
2
=
2
10×0.2
2
=0.2 kgm
2
Angular acceleration α=
I
τ
=
0.2
10
=50 rad/s
2
Initial angular velocity w
i
=0
Using w
f
=w
i
+αt
Or w
f
=0+50×6=300 rad/s
Hope It Helps ☺
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