Question

Q4. Construct a triangle ABC in which BC = 5.7cm, B = 45° and AB – AC = 3cm.​

Answer 1

Answer:

Step I: Draw the line segment BC = 8 cm and at point B, make an angle of 45°, say ∠XBC. Step II: Cut the line segment BD = 3.5 cm (equal to AB − AC) on ray BX. Step III: Join DC and draw the perpendicular bisector PQ of DC. Step IV: Let it intersect BX at point A.

Answer 2

Answer:

Hence the triangle is formed with BC= 5.7cm , B = 45°, AB - AC = 3cm

Step-by-step explanation:

      1. Draw base BC of length 5.7cm

      2. Now, draw ∠B = 45° , let the ray be BX.

      3.Open the compass to length AB - AC = 3cm

Since AB -AC = 3cm is positive

so, BD will be above line BC from point B as center, cut an arc on ray BX.

let the arc intersect BX at D.

     4. Join CD

     5. Now, we will draw perpendicular bisector of CD.

     6. Mark point A where perpendicular bisector intersects BD.

     7. Join AC

Therefore, ΔABC is the required triangle.