Question

Q4. Divide Rs 1500 into two parts so that 10% of larger part exceeds 8% of the smaller part by Rs. 60.
Find the larger and smaller part.

Answer 1

Let the smaller part be x. 
And the larger part be (1500-x) 

According to the question 

10% of (1500-x) - 8% of x = 60 

Or 10/100 of(1500-x) - 8/100 of x = 60 

Or150 - x/10 - 2/25 x = 60 

Or -5x-4x/50 = 60 - 150 

Or -9x = -90 * 50 

Or -9x = -4500 

Or +9x = + 4500 

Or x = 4500/9 

Or x = 500 

Larger part = 1500-500 
= 1000 

Smaller part = 500 

Answer 2

Let the larger part be X and therefore smaller part will be 1500-X.

Given that
10% of larger part = 8% of smaller part + 60
1/10 × X = {8/100 × (1500-x) } +60
X/10 = 2/25 ×(1500-X) +60
= 120 - 2X/25 +60
= 180 - (2X/25)

(X/10)+(2X/25) = 180

on simplifying...

9X/50 =180

X =. ( 180 × 50)/9
X = 1000

Therefore smaller part = 1500 -X = 500...

And we are done...
Happy to Help........