Question

Q4. Evaluate using algebraic identities: (999)2​

Answer 1

Answer:

998001

Step-by-step explanation:

(999)^2= (1000-1)^2

= ( 1000000+1-(2×1000×1))

= ( 1000001-2000)

= ( 998001)

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Answer 2

Hey mate,

Your answer is 998001.

Step-by-step explanation:

999*999

=(1000-1) (1000-1)

=(1000-1)^2

We know (x-y)^2= x^2+y^2-2xy

=1000^2+1^2-2*1000*1

=10,00,000+1-2000

=998001