Math, asked by nishantchauhan31, 8 months ago

Q4
If 2x + 3y = 5 and xy = 2, then find the value of 8x3+27y3

Answers

Answered by Anonymous
2

Answer:

=8x³+27y³

=(2x)³+(3y)³

=a³+b³=(a+b) (a²-ab+b²)

=(2x+3y)[(2x²)-2x*3y+(3y)²]

[2x+3y=5 because it is given]

=5(4x²-6xy+9y²)

=5(4x²-6*2+9y²).

[6xy =6*2 because it is given that xy=2]

=5(4x²-12+9y²)

=5[(2x)²-2*2x*3y+(3y)²].

[since (a-b)²=a²-2ab+b²]

=5(2x+3y)². [2x+3y=5 given]

=5*(5)²

=5*25

=125

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