Question

Q4. If a=7,b=2,c=1, find the value of (16bc - 5ab)/(abc-3b2).​

Answer 1

Answer:

a,b,c,d are in proportion

⇒ad=bc

Now

LHS:

(5a+7b)(2c−3d)

=10ac−15ad+14bc−21bd

=10ac−21bd−ad

RHS

(5c+7d)(2a−3b)

=10ac−15bc+14ad−21bd

=10ac−21bd−ad

⇒LHS=RHS

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

a,b,c,d are in proportion

⇒ad=bc

Now

LHS:

(5a+7b)(2c−3d)

=10ac−15ad+14bc−21bd

=10ac−21bd−ad

RHS

(5c+7d)(2a−3b)

=10ac−15bc+14ad−21bd

=10ac−21bd−ad

⇒LHS=RHS