Q4. If the point (3, 5) lies on the graph of 7x + 3y - 1) = 5a. Then find the value of a, also find the equation in
the form of ax + by + c = 0
Answers
Answered by
1
Answer:
7x+3y-1=5a
putx=3 and y=5
7×3+3×5-1=5
21+15-1=5a
7=5a
7\5=a
and the value in ax+by+c=0
7x+3y-1=5a
7x+3y=5×7\5-1
7x+3y-6=0
Answered by
1
Answer:
7x+3y-1=5a
put x=3and y =5
7(3)+3(5)-1 =5a
21+15-1=5a
7=5a
7/5=a
the value is ax+by +c=0
7x+3y-1=5a
7x+3y =5 ✖ 7/5-1
7x+3y=6
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