Q4. Plot the points A(-4,4) B(-6,0) C(-4,4) & D(-2,0)
Join A,B,C and D. Name the figure so obtained. Also write the co-
ordinate of point of intersection of diagnols.
Answers
Answer:
Step-by-step explanation:
Coordinates of the points,
A( -4 , 4 ) , B( - 6 , 0 ) , C( -4 , -4 ) and D( -2 , 0 )
We need to plot the points in the coordinate plane and name the figure. Find the Area of the Figure.
Graph is attached after plotting.
ABCD is a Rhombus as opposite sides are parallel and all sides are equal and Diagonals are perpendicular bisector of each other.
Area of the Rhombus ABCD = Area of the ΔABD + Area of the ΔACD
From the figure,
In ΔABD
Base = 4 unit
Height = 4 unit
In ΔACD
Base = 4 unit
Height = 4 unit
Area of the Rhombus ABCD = 1/2 × Base × Height + 1/2 × Base × Height
= 1/2 × 4 × 4 + 1/2 × 4 × 4
= 8 + 8
= 16 unit²
Therefore, Figure we obtained is Rhombus and Area is 16 unit².
Given : points A(–4, 4), B(–6, 0), C(–4,–4) and D(–2, 0)
To Find : figure obtained by joining the points in the order
Solution:
points A(–4, 4), B(–6, 0), C(–4,–4) and D(–2, 0)
Plot A(–4, 4)
Go 4 units left from origin and then 4 units above
B(–6, 0)
Go 6 unit left of origin
C(–4,-4)
Go 4 units left from origin and then 4 units below
D(–2, 0)
Go 2 unit left of origin
Join AB , BC , CD and AD
AB = BC = CD = AD = 2√5
BC = 4 and AD = 8 BC ≠AD
Hence figure obtained by joining the points in the order is a rhombus
point of intersection of diagonals = ( -4 , 0)
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