Q4 Prove that 6+5 is irrational
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Step-by-step explanation:
prove 6+√5is a irrational nos
Let us assume, to the contrary, that 6+√5 is irrational.
So we can find two integers numbers p and q(≠0), in the following way,
6+√5 = p/q [where p and q are co-prime]
Rearranging,
√5 = p/q - √6
√5 = [p - √6q]/q
But [p - √6q]/q is a rational nos
By fact √5 is a rational nos
our assumption is wrong
6+√5 is irrational nos
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