Question

Q4. SOLVE:- 3X2-X-2=0 BY THE METHOD
OF COMPLETING THE SQUARE.​

Answer 1

Step-by-step explanation:

The first term is, 3x2 its coefficient is 3 .

The middle term is, -x its coefficient is -1 .

The last term, "the constant", is -2

Step-1 : Multiply the coefficient of the first term by the constant 3 • -2 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -1 .

-6 + 1 = -5

-3 + 2 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 2

3x2 - 3x + 2x - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (x-1)

Add up the last 2 terms, pulling out common factors :

2 • (x-1)

Step-5 : Add up the four terms of step 4 :

(3x+2) • (x-1)

Which is the desired factorization

Answer 2

Answer:

heya mate ☺

$3x ^{2} - x - 2 = 0\\ \\ = > 3x ^{2} - (3 - 2)x - 2 = 0 \\ \\ = > 3x ^{2} - 3x + 2x - 2 = 0 \\ \\ = > 3x(x - 1) + 2(x - 1) = 0 \\ \\ = > (x - 1)(3x + 2) = 0 \\ \\ either \: x - 1 = 0 \\ \\ = > x = 1 \\ \\ or \: 3x + 2 = 0\\ \\ = > 3x = - 2 \\ \\ = > x = \frac{ - 2}{3}$

♡ hope it helps u mate ♡

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