Q4) Solve
(4M)
a) Subtract 6x3 5x2 + 4x - 3 from the sum of x + 2x2 – 3x3 and 2 - x2 + 6x - x3
b) if x = 202 + 3b2 - 5,
Answers
Answered by
0
Answer:
Sum of x+2x
2
−3x
3
and 2−x
2
+6x−x
3
=(x+2x
2
−3x
3
)+(2−x
2
+6x−x
3
)
=x+2x
2
−3x
3
+2−x
2
+6x−x
3
=2+7x+x
2
−4x
3
Now, Subtract 6x
3
−5x
2
+4x−2 from 2+7x+x
2
−4x
3
=(2+7x+x
2
−4x
2
)−(6x
3
−5x
2
+4x−2)
=2+7x+x
2
−4x
3
−6x
3
+5x
2
−4x+2
=4+3x+6x
2
−10x
3
Ans=4+3x+6x
2
−10x
3
Step-by-step explanation:
hope it's helpful to uh.
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