Math, asked by aishshamchavan5856, 4 months ago

Q4) Solve any two of the following subquestions
(8)
1) Prove the theorem of cyclic quadrilateral
2) A bird was flying in a line parallel to the ground from north to south at a
height of 2000 metres. Tom, standing in the middle of the field, first
observed the bird in the north at the angle of 30°. After 3 minutes, he
again observed it in the south at an angle of 45°. Find the speed of the
bird in kilometres per hour (V3 = 1.73​

Answers

Answered by Itzraisingstar
67

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1:A rectangle has a length of 8 cm, and a width of 3 cm. Find its perimeter  and area?​

The ratio between the diagonals and the sides can be defined and is known as the Cyclic quadrilateral theorem. If there's a quadrilateral that is inscribed in a circle, then the product of the diagonals is equal to the sum of the product of its two pairs of opposite sides.

2: A bird was flying in a line parallel to the ground from north to south at a  height of 2000 metres. Tom, standing in the middle of the field, first

observed the bird in the north at the angle of 30°. After 3 minutes, he

again observed it in the south at an angle of 45°. Find the speed of the

bird in kilometres per hour (V3 = 1.73)?

Answer: 109.20

Step-by-step explanation: a bird is flying to the north at an angle of elevation of 30°.

Using tan 30°=opp/adj

=1/√3=2000/BC

BC=2000√3m-------------(1)

Now, the bird fly to south at an angle of elevation of 45°

= tan45°=opp/adj

=1=2000/CD

=CD=2000m----------------(2)

Therefore,distance=BC+CD

2000√3+2000 =2000(√3+1)m

But we want the answer in km

2000(√3+1)/1000 = 2(√3+1)km

Bird takes 3min=3/60hr

Therefore,speed=distance/time

=2(√3+1)/3/60

=2(√3+1)×60/3

=20(2√3+2)

=40√3+40. (√3=1.73)

=40×1.73+40

=69.20+40

=109.20km/hr.

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Answered by Anonymous
28

Answer:

1:A rectangle has a length of 8 cm, and a width of 3 cm. Find its perimeter and area?

The ratio between the diagonals and the sides can be defined and is known as the Cyclic quadrilateral theorem. If there's a quadrilateral that is inscribed in a circle, then the product of the diagonals is equal to the sum of the product of its two pairs of opposite sides.

2: A bird was flying in a line parallel to the ground from north to south at a height of 2000 metres. Tom, standing in the middle of the field, first

observed the bird in the north at the angle of 30°. After 3 minutes, he

again observed it in the south at an angle of 45°. Find the speed of the

bird in kilometres per hour (V3 = 1.73)?

Answer: 109.20

Step-by-step explanation: a bird is flying to the north at an angle of elevation of 30°.

Using tan 30°=opp/adj

=1/√3=2000/BC

BC=2000√3m-------------(1)

Now, the bird fly to south at an angle of elevation of 45°

= tan45°=opp/adj

=1=2000/CD

=CD=2000m----------------(2)

Therefore,distance=BC+CD

2000√3+2000 =2000(√3+1)m

But we want the answer in km

2000(√3+1)/1000 = 2(√3+1)km

Bird takes 3min=3/60hr

Therefore,speed=distance/time

=2(√3+1)/3/60

=2(√3+1)×60/3

=20(2√3+2)

=40√3+40. (√3=1.73)

=40×1.73+40

=69.20+40

=109.20km/hr.

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