Question

Q4. The beaker in the given diagram has copper
sulphatesolution:
a) Write an equation to show what will happen when
current is passed through the solution.
b) Indicate to which electrode will the metal get deposited?
c) Which electrode will lose metal?
d) What happens to the metal that is lost from one of the
electrode?
​

Answer 1

Answer:

I) when current is passed

the copper sulphate loses copper the copper gets deposited in cathode

II) Cathode

III) Anode

IV) The metal will deposit in another electrode

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