Question

Q4. The point of intersection of the
line representing the equation
3x=2y+1 and 2x=3y-1 is?​

Answer 1

Answer:

Solution of the linear equation is x=3, y=4

Shaded region in black.

Step-by-step explanation:

Given : Equation 1- 3x-2y-1=03x−2y−1=0

Equation 2- 2x-3y+6=02x−3y+6=0

To find : Solve the following system of linear equations graphically 3x-2y-1=03x−2y−1=0 and 2x-3y+6=02x−3y+6=0 shade the region bounded by the lines and x-axis.

Solution : Graph is attached below.

The graph represent the area of the equation 1 , equation 2 and x-axis.

The point satisfying the equation is the intersection point of the graph

The intersection point of the graph is (3,4).

And the area under equation 1 , equation 2 and x-axis is the shaded region in black between the points (-3,0),(0,2),(3,4),(0.333,0) and x-axis.

Answer 2

Answer:

The values of x and y are 1 and 1 ....So the point of intersection is (1,1)

Step-by-step explanation:

3x-2y = 1 and 2x-3y = -1 are the given equations

by solving

3x-2y = 1 (multiply by 2)

2x-3y = -1( multiply by 3)

___________

Now...after mulitiplication

6x-4y = 2

6x-9y = -3

(-) (+) (+) ------on changing the symbol

______________

5y = 5

y = 1

Now substitute y=1 in the equation 3x-2y = 1

3x - 2(1) = 1

3x-2 = 1

3x = 3

x = 1

So the answer is (1,1)

Hope you got the right answer

If you want to check this...then substitute the values of x and y in any of the equation and check whether the LHS is equal to RHS