Question

Q4. The remainder when x cube+ 3x square + 3x + 1 divided by x+1 is :

Answer 1

Answer:

Apply remainder theorem

=>x + 1 =0

=> x = - 1

Replace x by – 1 we get

=>x3+3x2 + 3x + 1

=>(-1)3 + 3(-1)2 + 3(-1) + 1

=> -1 + 3 - 3 + 1

=> 0

Remainder is 0

Answer 2

Step-by-step explanation:

Apply remainder theorem

•x+1=0

•x = -1

Replace x by -1 we get

•x³ + 3×2 + 3x+1

•(-1)3 + 3(-1)2 + 3(-1) + 1

•-1+3-3+1

•0

Remainder is 0

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