Q4.
The resultant of two vectors P and Q is R. If the magnitude of Q is doubled, the new resultant becomes perpendicular to P. Then the magnitude of R is ?
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Answer:
Explanation:
Let the angle between two vectors P and Q be α and their resultant is = R
Thus,
R² = P²+Q²+ 2PQcosα --- (1)
When Q is doubled then let the resultant vector be R1, thus -
R² = P²+ 4Q²+ 4PQcosα --- (2)
Again by the given condition R1 is perpendicular to P, hence -
4Q² = R² + P² --- (3)
Combining equation 2 and 3 we will get -
= R² = P²+ P² + R1² + 4PQcosα
= 2PQcosα = -P² --- (4)
Combining equation 1 and 4 we will get -
= R² = P²+ Q² - P²
= R = Q
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