Question

Q4. Zeros of p(x) = x^2 - 2x -3 are​

Answer 1

Answer:

x^2-2x-3

x^2-3x+x-3

x(x-3) +1 (x-3)

(x+1) (x-3)

x+1=0

x= -1

x-3=0

x= 3

zeroes of p(x) =x^2-2x-3 are -1 and 3

Answer 2

Step-by-step explanation:

refer to the attachment