Math, asked by manasagadi, 22 hours ago

Q44. 'A' Is 40% less efficient than 'B' who can do the same work in 20% less time than 'C'. If A and B together can complete 80% of work in 12 days, then in how many days 60% of work can be completed by B and C together.
(a) 2 days b
b) 4 days
(c) 6 days
(d) 8 days
(e) 10 days​

Answers

Answered by yashwardhan01558
0

Answer:

16 days

Step-by-step explanation:

Let the efficiency of B be 100.

Efficiency of A will be = 100 × [140/100] = 140

Efficiency of C will be = 100 × [80/100] = 80

Efficiency ratio of A, B and C = 140 : 100 : 80 = 7 : 5 : 4

Total work = (7 + 5 + 4) × 20 = 320

35% of total work = 320 × [35/100] = 112

35% of total work A will complete in = 112/7 = 16 days

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