Question

Q44 For the circuit shown in below. Figure, determine (a) the battery voltage V. (b) the total resistance of the
circuit and (c) the values of resistance of resistors R1, R2 and R3, given that the p.d.'s across R1, R2 and R3 are
5 V/2Vand 6 V respectively.
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Answer 1

Answer:

Si unit of voltage is ampere

Explanation:

I dont know your answer

Answer 2

Given :

$V_1 = 5V\\V_2 = 2V\\V_3 = 6V$

$I = 4A$

$R_1 , R_2 and R_3$ are in series.

To find:

Total resistance , Battery voltage , values of resistance of resistors.

Solution:

Battery voltage will be the sum of individual voltages across the resistors since they are in series:

a)  $V= V_1+V_2+V_3$  $= 5+2+6 = 13 V$

b)  Total resistance also will be sum of individual resistances in series given by : $R = R_1 + R_2 + R_3$$= \frac{V_1}{I} + \frac{V_2}{I}+\frac{V_3}{I}$

$= \frac{5}{4} + \frac{2}{4}+\frac{6}{4} = 3.25 \Omega$

c) Values of resistances :  $R_1 = \frac{5}{4} = 1.25\Omega$

$R_2 = \frac{2}{4} = 0.5 \Omega$

$R_3= \frac{6}{4} = 1.5\Omega$