Question

Q44
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The voltmeter shown in figure reads 18V across the 50 Q resistor. Find the approximate resistance of the voltmeter.
30 V
5002
24 22​

Answer 1

Answer:

The voltage across the 24 ohms resistor is 30−18=12 v

The current flowing is 12v/24Ω=0.5 A

The current through the 50 Ω resistor is 18v/50Ω=0.36 A

So the current through the voltmeter is 0.5A−0.36A=0.14 A

The resistance of the voltmeter is 18v/0.14A=128.6Ω