Question

Q4A ball is dropped from a height 'h'. The velocity of the
ball when it reaches the ground is 10 m/s. Find height 'h'(
take g = 10 m/s2)​

Answer 1

Answer:

5 m

Explanation:

given,

u is 0

v is 10m/s

we know,

v²-u²=2gh

100-0= 2*10*h

100/20= h

hence,

h= 5 m

Answer 2

Answer:

5m

Explanation:

g = a

h = S

Starting speed (u) = 0

last speed (v) = 10 m/s

a = g = 10 m/s^2

so, v^2 - u^2 = 2as

or v^2 -u^2 = 2gh

so, (10)^2 - (0)^2 = 2*10*h

=> 100-0 = 20*h

=> 20*h = 100

=> h = 100/20

=> h = 5 m

I hope it is useful for you.