Question

Q5)ਇੱਕ ਤ੍ਰਿਭੁਜ ਵਿੱਚ ਸੱਭ ਤੋਂ ਵੱਡੀ ਭੁਜਾ ਸੱਭ ਤੋ ਛੋਟੀ ਭੁਜਾ ਤੋ ਦੁਗਣੀ ਹੈ ਅਤੇ ਤੀਸਰੀ ਭੁਜਾ ਸੱਭ ਤੋ ਛੋਟੀ ਭੁਜਾ ਤੋ 3 ਸਮ ਜਿਆਦਾ ਹੈ।ਜੇਕਰ ਤ੍ਰਿਭੁਜ ਦਾ ਪਰਿਮਾਪ 203 ਸਮ ਤੋਂ ਜਿਆਦਾ ਜਾਂ ਬਰਾਬਰ ਹੈ ਤਾਂ ਛੋਟੀ ਭੁਜਾ ਦੀ ਘੱਟੋ ਘੱਟ ਲੰਬਾਈ ਹੋਵੇਗੀ:The longest side of a triangle is twice the shortest side and third side is 3 cm longer than shortest side. If perimeter of triangle is more than or equal to 203 cm then minimum length of the shortest side is: *​

Answer 1

Answer:

If the perimeter of the triangle is more than 166 cm, then find the minimum length of the shortest side. Let the length of shortest side be x cm. Hence, the minimum length of shortest side be 41 cm.

Answer 2

Minimum length of the shortest side is 50 cm if The longest side of a triangle is twice the shortest side and third side is 3 cm longer than shortest side and perimeter of triangle is more than or equal to 203 cm

Given:

• A triangle
• The longest side of a triangle is twice the shortest side
• Third side is 3 cm longer than shortest side
• Perimeter is more than or equal to 203 cm

To Find:

• Minimum length of the shortest side

Solution:

• Perimeter of a triangle is sum of lengths of all three sides of the triangle.

Step 1:

Assume that Shortest side is x  cm

Then Longest sides = 2x  cm

and Third side = x + 3 cm

Step 2:

Perimeter of more than or equal to 203 cm

x + 2x + x + 3 ≥ 203

=> 4x ≥ 200

=> x ≥ 50

Hence, minimum length of the shortest side is 50 cm