Question

Q5.
3
The breaks applied to a car produce
an acceleration of 6 metre per
second square in the opposite
direction to the motion. If the car
takes 2 seconds to stop after the
application of brakes. Calculate the
distance it travels during this time.​

Answer 1

Answer:

Acceleration in opposite direction = -6 m/s²

Time taken by the car to stop = 2 s

We need to find the distance travelled during this time.

So, using first equation of motion :

⇒ v = u + at

⇒ 0 = u + (-6)(2)

⇒ -u = -12

⇒ u = 12 m/s

So, initial speed of the car is 12 m/s.

Now, using second equation of motion :

⇒ s = ut + ½at²

⇒ s = 12×2 + ½(-6)(2)²

⇒ s = 24 + (-3)(4)

⇒ s = 24 - 12

⇒ s = 12 m

Hence, the Distance travelled by the car during the time brakes were applied was 12 m.