Question

Q5 A car starts from rest, acquires a velocity of 72 km/hr in 10 sec. Find the acceleration and force applied on the body

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=2\:m/s^{2}}}}$

$\green{\tt{\therefore{Force\:applied=2m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Final \: velocity(v) = 72 \: kmh \\ \\ \tt: \implies Time(t) = 10 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Acceleration(a) = ? \\ \\ \tt: \implies Force \: applied(f) = ?$

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: m/s \\ \\ \tt \circ \:Final \: velocity = 72 \times \frac{5}{18} = 20 \: m/s\\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 20 = 0 + a \times 10 \\ \\ \tt: \implies 20 = a \times 10\\ \\ \tt: \implies a = \frac{20}{10} \\ \\ \green{\tt: \implies a = 2 \: m/{s}^{2} } \\ \\ \bold{For \: Force \: applied : } \\ \tt: \implies F= ma \\ \\ \tt: \implies F= m \times 2 \\ \\ \green{\tt: \implies F= 2m}$

Answer 2

$\tt{\huge{\green{Solution_{BQ} \::- }}}$

QUESTION :

Q5 A car starts from rest, acquires a velocity of 72 km/hr in 10 sec. Find the acceleration and force applied on the body.

SOLUTION :

Given Info :

U = 0 m/s

V = 72 km/hr = 72 × 5/18 m/s = 20 m/s.

Time = 20 Seconds.

According to the first Equation of Motion,

a = v - u / t

=> 20 / 10

=> 2 m/s^2

Suppose that the car has a mass M kg.

By Newton's Law ,

F = m × a

=> F = 2M.

Answer :

The acceleration attained by the car above = 2 m/s^2.

The force applied on the car ( internally ) = 2 M Newton.