Q5. A floor is 4.5 m long and 3.6 m wide is to be covered with tiles. A 6 cm square tile costs ₹23.25. What will be the cost to cover the floor with these tiles?
Answers
Answer:
Solution :
A floor is 4.5 m long and 3.6 m wide.
The area of the floor is A=l\times bA=l×b
A=4.5\times 3.6A=4.5×3.6
A=16.2m^2A=16.2m
2
Converting m into cm,
1 m = 100 cm
1 m² = 10000 cm²
So, 16.2m^2=16.2\times 10000=162000cm^216.2m
2
=16.2×10000=162000cm
2
Area of square tile is 6 cm².
Number of tiles required to cover the floor is
n=\frac{\text{Area of floor}}{\text{Area of tile}}n=
Area of tile
Area of floor
n=\frac{162000}{6}n=
6
162000
n=27000n=27000
Cost of 1 tile is Rs.23.25.
Cost of 27000 tile is 27000\times 23.25=Rs.62775027000×23.25=Rs.627750
Therefore, The cost to cover the floor with these tiles is Rs.627750.
Answer:
Length of the floor = 4.5 m = (4.5 × 100) cm = 450 cm Width of the floor – 3.6 m – (3.6 × 100) cm = 360 cm
∴ Area of the floor – (450 × 360) cm2 = 162000 cm2 Side of a square tile = 6 cm
∴ Area of one square tile = (6 × 6) cm2 = 36 cm2 Number of tiles required to cover the floor = Area of floor/ Area of one tile = 4500 Now, cost of one tile = ₹ 23.25
∴Cost of 4500 tiles =₹ (23.25 × 4500) = ₹ 104625