Question

Q5 a
I will surely him/ her brainliest who gives
It's correct answer

Answer 1

Let the three terms be a/r,ar and a

When we take the product of three terms the common ratio gets cancelled 

a/r*a*ar=a³=(-1)^3=-1

a=-1

sum of three terms is 13/12

a+a/r+ar=13/12

-1-1/r-r=13/12

-1/r-r=13/12+1

-1/r-r=25/12

(r-9)(r-16)=0

r=9 or r=16

the terms for r=9

-1,-9,-1/9

for r=16

-1,-16,-1/16

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