Q5. A stone is dropped from a height of 80 m. Find
(i) Time of fall
(ii) Velocity after 2 seconds of free fall
(iii) Velocity with which it hits the ground.
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Answer:
The height = h = 80 m.
The initial velocity = 0 m/s.
Now, We know that, t = √2h/g.
⇒ t = √2*80/9.8
⇒ t = √160/9.8
⇒ t = √16
⇒ t = 4 s
Now, We know that, v = u + gt.
⇒ v = 0 + 9.8*2
⇒ v = 19.6 m/s
Finding, the velocity with which it hits the ground.
⇒ v = u + gt
⇒ v = 0 + 9.8*4
⇒ v = 39.2 m/s
Hence, Time of fall = 4 s, velocity after 2 seconds of free fall = 19.6 m/s and velocity with which it hits the ground = 39.2 m/s.
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