Question

Q5/A thundercloud produce electric field of magnitude 28*103 N/c at ground level you hold 22 cm *28 cm sheet of paper horizontally below the cloud find a- what is the electric flux b-what would the flux be if you tilt the sheet of paper by 300 c-what would the flux be if you hold the sheet vertically
help me please​

Answer 1

Answer:

A thundercloud produces a vertical electric field of magnitude. kN C at ground level. You hold. #)ﾞ! ﾎ a cm cm sheet of ... N m C. N m C. (c) What would the flux be if you hold the sheet of paper vertically?

Answer 2

Explanation:

Given A thundercloud produce electric field of magnitude 28*103 N/c at ground level you hold 22 cm *28 cm sheet of paper horizontally below the cloud find a- what is the electric flux b-what would the flux be if you tilt the sheet of paper by 300 c-what would the flux be if you hold the sheet vertically

We need to find the electric flux. So we have

Electric flux φ = EA

                       = 28 x 10^3 N/C x 0.0616 sq m (Since 22 x 10^-2 x 28 x 10^-2 = 0.0616 sq m)

                       = 1.72 x 10^3 N m^2 / C

                      = 1724.8 N-m^2 /C

Now we need to find the flux if the sheet of paper is tilted by 30 degree

           So φ = EA cos theta

                   = 1.72 x 10^3 N-m^2 /C x cos 30

                   = 1.72 x 10^3 x √3 / 2

                   = 1.48 x 10^3 N-m^2 / C

Now we need to find the flux if the sheet of paper is held vertically.

The flux will be zero since the electric field will be parallel to the sheet of paper

Reference link will be

https://brainly.in/question/20078427