Question

Q5 and Q7-ii ...... can u help me...

Answer 1

Answer:

Q.5. Given equation, 6x^2 - bx +2=0

And, D=1

Since, D= b^2-4ac

So, 1= b^2-4×6×2

1= b^2-48

b^2 = 49

So, b= 7.

Q.7.

(i) 4x^2 + kx +9= 0

Since,the equation has equal and real roots,

So, k^2 - 4×4×9=0

k^2= 144

k = 12

(ii){2(k-12)}^2 - 4(k-12)×2=0

= (2k-24)^2 - 4(k-12)×2=0

= 4k^2+576-96k - 8k +96=0

= k^2+144-24k-2k+24=0

= k^2-26k+168=0

= k^2-14k-12k+168=0

= k(k-14)-12(k-14)=0

= (k-12) (k-14) =0

So, k=12 or k =14

Answer 2

I hope it's helpful for you.