Question

Q5. Asif is 5 years younger than Qasim. Four years later, Qasim will be twice as old as
Asif. Find their present ages​

Answer 1

Answer:

Age of Qasim =  6 year

Age of Asif = 1 year

Step-by-step explanation:

Let :

Age of Qasim = x

Age of Asif = x -5

After 4 years there age will be:

Age of Qasim = x+4

Age of Asif = x-5+4 = x-1

We are given: Four years later, Qasim will be twice as old as  Asif.

Age of Qasim = 2 (Age of Asif)

x+4=2(x-1)

x+4=2x-2

2x-x=4+2

x=6

So, We get x = 6

The present ages will be:

Age of Qasim = x = 6 year

Age of Asif = x -5 = 6-5 = 1 year

Okay