Q5) Calculate excess pressure of soap bubble of radius 4cm (surface tension = 0.025 N/m)
1 point
a) 5 N/m²
b) 10 N/m²
c) 1.25 N/m²
d) 2.5 N/m²
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Answer:
The excess pressure is calculated as ΔP=
r
4T
ΔP=
0.5×10
−2
4×25×10
−3
=20N/m
2
1Pa=1N/m
2
⇒ΔP=20Pa
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